Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together ?
Solution
Correct Answer: Option B
In this type of problems the formulae is \(\left(5x-30\right)\times\frac{12}{11}\)
x is replaced by the first interval of given time Here i.e 8
\(\left(5\times8-30\right)\times\frac{12}{11}\)
= \(\frac{120}{11}\)min
Therefore the hands will be in the same straight line but not
together at \(\frac{120}{11}\) min.past 8.
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