What is the right most integer of the expression \(65776^{759}\;+\;54697^{467}\) ?
Correct Answer: Option C
Last digit for the power of 6 is 6 (always)
Power cycle of 7 is 7, 9, 3, 1.
Now 467/4 gives a remainder of 3
Then the last digit is \(7^3\) = 3
Last digit is 6 + 3 = 9.
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