Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
Solution
Correct Answer: Option C
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ l0) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
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