A person walking 6/7 of his usual rate is 30 minutes late. What is his usual time ?
Solution
Correct Answer: Option C
Let t be the usual time. If the usual rate is 1 unit, then the unusual rate is 6/7.
Balance by the distance,
1 x t = (6/7)(t + 30)
7t = 6(t + 30)
we get t as,
t = 180 minutes = 3 hrs.
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