Correct Answer: Option C
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
So, (100 + 100)/8 = 3x
=> 24x = 200
=> x = 25.
So, speed of the faster train = (50/3) m/sec
= (50/3) x (18/5) km/hr
= 60 km/hr.
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