x²+y²+z²=4,x+y-z=8 হলে yz+zx-xy এর yz+zx-xy এর মান-
Solution
Correct Answer: Option B
আমরা জানি ,
(x+y-z)²=x²+y²+(-z)²+2(xy-zx-yz)
বা,xy-xz-yz=(x+y-z)²-(x²+y²+z²)/2
বা,yz+zx-xy= x²+y²+z²-(x+y-z)²/2
বা,yz+zx-xy= 4-(8)²/2
=(4-64)/2
=-60/2
=-30
(x+y-z)²=x²+y²+(-z)²+2(xy-zx-yz)
বা,xy-xz-yz=(x+y-z)²-(x²+y²+z²)/2
বা,yz+zx-xy= x²+y²+z²-(x+y-z)²/2
বা,yz+zx-xy= 4-(8)²/2
=(4-64)/2
=-60/2
=-30
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