Unit's digits of a 2 digit number is 5 more than the ten's digit, and if we put the digits of the number in reverse order, the new number is 4 less than twice the original number. The number is :-
Correct Answer: Option B
Let the digits of the number be a and b.
∴ the number is 10a + b
Given Unit's digits of a 2 digit number is 5 more than the ten's digit
∴ b = 5 + a -----[1]
On reversing the digits number obtained = 10b + a
Now, this number is 41 less than twice the original number
∴ 2(10a + b) – (10b + a) = 4
⇒ 19a – 8b = 4 -----[2]
Putting the value of b = 5 + a from equation [1] in equation [2]
⇒ 19a – 40 – 8a = 4
⇒ 11a = 44
⇒ a = 44/11 = 4
∴ b = 5 + a
= 5 + 4
= 9
The original number is 49
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