A tin contains a mixture of coke and pepsi in the ratio of 7 : 3 and another tin contains the coke and pepsi in the ratio of 5 : 4. In what proportion should the solution of the two tins be mixed to achieve a perfect proportion of 2 : 1(inn which coke is 2 times of pepsi)?
Solution
Correct Answer: Option B
According to the question, in,
The mixture M1-
Coke : pepsi = 7 : 3
The mixture M2-
Coke : pepsi = 5 : 4
Proportion of coke in the mixture M1 = 7/10,
Proportion of coke in the mixture M2 = 5/9,
Proportion of the new mixture = 2/3 (required)
According to the law of mixture-
\(Required\ ratio = \frac{{\frac{2}{3} - \frac{5}{9}}}{{\frac{7}{{10}} - \frac{2}{3}}} = \frac{{\frac{1}{9}}}{{\frac{1}{{30}}}} = \frac{{10}}{3} = 10:3\)
Hence, the required ratio is 10 : 3.
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