The amount of alcohol in two varieties of whiskey are 27% volume/volume and 42% volume/volume. In what ratio should they be mixed so that the mixture has 33% volume/volume alcohol?
Solution
Correct Answer: Option B
Let the whiskeys are mixed in amounts M litres and N litres.
⇒ Amount of alcohol in first variety = 0.27M
⇒ Amount of alcohol in second variety = 0.42N
Total amount of mixture = (M + N) litres
Amount of alcohol in mixture = 33% volume/volume = 0.33(M + N)
⇒ 0.27M + 0.42N = 0.33(M + N)
⇒ 0.09N = 0.06M
⇒ M/N = 3/2
∴ Ratio in which they should be mixed is 3 : 2.
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