Two friends F1 and F2 go from home to temple and return to home. F1 travels through a boat which has speed 20 kmph and river flows at 5 kmph while F2 travels by a bullock cart which has speed 24 km/hr. Which one of two return to home first ?
Correct Answer: Option B
Let the distance be ‘D’.
Speed of bullock cart = 24 kmph
Time taken by F2 in going to temple and back home= Distance/speed = 2 × D/24 = D/12 = 0.083D
Speed of boat=20kmph; Speed of stream= 5kmph
Time taken by F1 in going to temple and back home
\(= \left[ {\frac{D}{{Upstream}} + \frac{D}{{downstream}}} \right] = \left[ {\frac{D}{{20 - 5}} + \frac{D}{{20 + 5}}} \right] = \frac{{8D}}{{75}} = 0.106D\)
Clearly, F2 is taking lesser time. Hence, he will reach first.
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