Two trains are travelling in the same direction at 50 km/h and 30 km/h respectively. The faster train crosses a man sitting in the slower train in 18 seconds. Find the length of the faster train.
Correct Answer: Option D
Relative speed of the faster train with respect to slower train = (50-30) km/h = 20 km/h
= 20 × 5/18 m/s =50/9 m/s,
Distance travelled by the faster train in crossing the man = length of the faster train (let X),
(Note): When a train passes a stationary man/object, the distance travelled by the train would be equal to the length of the train.
Now,
∵ Distance = speed × time
⇒ X = (50/9) × 18 = 100 meters.
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