The odds against an event A are 5:3 and odds in favor of another independent event B and 6:5. The chances that neither A nor B occurs is
Correct Answer: Option B
The odds against an event A are 5:3
Probability of not occurring the individual event A = 5/8
Probability of occurring the individual event A = 3/8
Again ,
odds in favor of another independent event B and 6:5
Probability of occurring the individual event B = 6/(6+5) = 6/11
Probability of not occurring the individual event B = 5/(6+5) = 5/11
The chances that neither A nor B occurs is = Probability of not occurring event A × probability of not occurring event B [As the two events are independent therefore multiplication will occur]
\(= \;\frac{5}{8} \times \frac{5}{{11}}\)
\(= \frac{{25}}{{88}}\)
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