The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle?
Correct Answer: Option B
let ABC be the isosceles triangle, the AD be the altitude
Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]
since in an isoceles triange the altitude bisects the base so
BD = DC = 16-x
In a triangle ADC = \(\left(AC\right)^2=\left(AD\right)^2+\left(DC\right)^2\)
\(x^2=8^2+\left(16-x\right)^2\)
\(\Rightarrow x=10\)
BC = 32-2x = 32-20 = 12 cm
Hence, required area = \(\frac12\ast BC\ast AD\) = \(\frac12\ast12\ast10\) = 60 sq cm
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