The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
Correct Answer: Option C
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = \(\frac{120}{100}\) and Increased breadth = \(\frac{120}{100}\)
New area = \(\frac{120}{100}x\ast\frac{120}{100}y=\frac{36}{25}xy\;m^2\)
The difference between the Original area and New area is:
\(\frac{36}{25}xy-xy\)
\(\frac{11}{25}xy\) Increase % = \(\left(\frac{\displaystyle\frac{11}{25}xy}{xy}\right)\ast100\) = 44%
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