What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?
Correct Answer: Option A
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = \(\left(41\times41\right)cm^2\)
Required number of tiles = \(\frac{1517\times902}{41\times41}\) = 814
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