Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.
Correct Answer: Option A
Let a = 13, b = 14 and c = 15.
Then \(s=\frac12\left(a+b+c\right)\) = 21
Area = \(\sqrt{\left[s\left(s-a\right)\left(s-b\right)\left(s-c\right)\right]}\)
= \(\sqrt{\left(21\times8\times7\times6\right)}\) = 84 sq.cm
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