The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
Correct Answer: Option C
Angle traced by hour hand in \(\frac{13}3\) hrs = \(\left(\frac{360}{12}\times\frac{13}3\right)^0\) = \(130^0\)
Angle traced by min. hand in 20 min = \(\left(\frac{360}{60}\times20\right)^0\) = \(120^0\)
Required angle = (130 - 120)º = 10º
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