Three unbiased coins are tossed.What is the probability of getting at least 2 heads?

A 1/4

B 1/2

C 3/4

D 1/3

Correct Answer: Option B

Here S= {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}.

Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}.

P(E) = n(E) / n(S)

= 4/8= 1/2