The probability of occurance of two two events A and B are 1/4 and 1/2 respectively. The probability of their simultaneous occurrance is 7/50. Find the probability that neither A nor B occurs.
Solution
Correct Answer: Option B
P ( neither A nor B) = \(P\left(\overline A\;and\;\overline B\right)\)
= \(P\left(\overline A\cap\overline B\right)\)
= \(P\left(\overline{A\cup B}\right)\)
= \(1-P\left(A\cup B\right)\)
= \(1-\frac{61}{100}=\frac{39}{100}\)
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