Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.

A 2/7

B 3/7

C 4/7

D 3/7

Solution

Correct Answer: Option A

Total number of persons = 9

 

Out of 9 persons 4 persons can be selected in \(9C_4\) ways =126

 

1 man,1 woman and 2 children can be selected in \(3C_1\times2C_1\times4C_1\) ways =36

So,required probability = 36/126 =2/7

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