In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ?

A 6/7

B 19/21

C 7/31

D 5/21

Correct Answer: Option D

Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁)

As remaining person can be any one among three couples left.

Required probability

= (⁵C₂ x ⁶C₁)/¹⁰C₅
= (10 x 6)/252

= 5/21