In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:

A 21/46

B 1/5

C 3/25

D 1/50

Solution

Correct Answer: Option A

Let S be the sample space and E be the event of selecting 1 girl and 2 boys.

 

Then, n(S) = Number ways of selecting 3 students out of 25

 

                = \(25C_3\) = 2300.

 

         n(E)= \(10C_1\times15C_2\) = 1050. 

 

P(E) = n(E)/n(s) = 1050/2300 = 21/46

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