Three unbiased coins are tossed. What is the probability of getting at most two heads ?
Solution
Correct Answer: Option D
Let S be the sample space.
Here n(S)= \(\mathbf2^\mathbf3\) = 8
Let E be the event of getting atmost two heads. Then,
n(E) = {(H,T,T), (T,H,T), (T,T,H), (H,H,T), (T,H,H), (H,T,H)}
Required probability = n(E)/n(S) = 6/8 = 3/4.
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