14 persons are seated around a circular table. Find the probability that 3 particular persons always seated together.
Solution
Correct Answer: Option C
Total no of ways = (14 – 1)! = 13!
Number of favorable ways = (12 – 1)! = 11!
So, required probability = \(\left(\frac{\left(\mathbf{11}\boldsymbol!\boldsymbol\times\mathbf3\boldsymbol!\right)}{\mathbf{13}\boldsymbol!}\right)\)
= \(\frac{39916800\times6}{6227020800}\)
= \(\frac{\mathbf{24}}{\mathbf{625}}\)
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