x+y=2, x2+y2= 4 হলে x3+y3 = কত?

A 8

B 9

C 16

D 25

Solution

Correct Answer: Option A

আমরা জানি,
(x+ y)2 =  x2 + 2xy + y2
⇒ 22=4+2xy
⇒ 4 = 4+2xy
⇒ 2xy = 0
xy=0


আবার,

(x+y)3= x3 + y3+ 3xy(x+y)

⇒(2)3 = x3 + y3+ 3 × 0 × 2

⇒ 8 = x3 + y

 x3 + y=8

 

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