1/x + 1/y = 3 এবং (1/x2) - (1/y2) = 9 হলে 1/x

1/x + 1/y = 3 এবং (1/x²) - (1/y²) = 9 হলে 1/x - 1/y = কত?

A 1

B 1/3

C 3

D 9

Solution

Correct Answer: Option C

দেওয়া আছে,
1/x + 1/y = 3
এবং (1/x²) - (1/y²) = 9

এখন,
(1/x²) - (1/y²) = 9
⇒ (1/x + 1/y)(1/x - 1/y) = 9
⇒ 1/x - 1/y = 9/3 [ 1/x + 1/y = 3 ]
∴ 1/x - 1/y = 3

Solution

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