Correct Answer: Option C
Required sum = (2 + 4 + 6 + ... + 30)
This is an A.P. in which a = 2, d = (4 - 2) = 2 and l = 30.
Let the number of terms be n.
Then,tn = 30 a + (n - 1)d = 30
=> 2 + (n - 1) x 2 = 30
=> n - 1 = 14
=> n = 15
Sn = (n/2)(a + l)
=(15/2) x(2 + 30)
= 240.
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