The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

A    1008

B    1015

C    1022

D    1032

Solution

Correct Answer: Option B

 

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7

   = 1008 + 7

   = 1015

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