Correct Answer: Option D
Let the cost of a chair and that of a table be Tk. x and Tk. y respectively.
Then, 10x = 4y or y = (5/2)x
So, 15x + 2y = 4000
=> 15x + 2 x (5/2)x = 4000
=> 20x = 4000
So, x = 200.
So, y = ((5/2) x 200) = 500.
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Tk. (2400 + 1500)
= Tk. 3900.
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