There are two numbers such that the sum of twice the first and thrice the second is 39, while the sum of thrice the first and twice the second is The largest of the two is :

A 6

B 8

C 9

D 12

Correct Answer: Option C

Let,

the numbers be x and y.

Then,

2x + 3y = 39...(i)

and

3x + 2y = 30 ...(ii) On solving (i) and (ii), we get : x = 6 and y = 9. larger number = 9