sin(9π/2+ø)=?

A sinθ

B −sinθ

C cosθ

D −cosθ

Solution

Correct Answer: Option C

  sin(9π/2+θ)
= sin{(9×180°)/2+θ}
= sin{(9×90°)+θ}
= cosθ
[Note: বিজোড় 90° হলে যে sinθ থাকবে তার বিপরীত cosθ হবে]

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