x2 - 4, x2 + 4x + 4 , x3 - 8 বীজগাণিতিক রাশির ল.সা.গু কত?
Solution
Correct Answer: Option A
১ম রাশি = x2 - 4
= x2 - 22
= (x + 2)(x - 2)
২য় রাশি = x2 + 4x +4
= x2 + 2.x.2 + 22
= (x + 2)2
= (x + 2)(x + 2)
৩য় রাশি = x3 - 8
= x3 - 23
= (x - 2) (x2 + 2.x + 22)
= (x - 2)(x2 + 2x + 4)
∴ নির্ণেয় ল. সা. গু = (x + 2)2(x - 2)(x2 + 2x + 4)
=(x + 2)2(x3 - 8)
= x2 - 22
= (x + 2)(x - 2)
২য় রাশি = x2 + 4x +4
= x2 + 2.x.2 + 22
= (x + 2)2
= (x + 2)(x + 2)
৩য় রাশি = x3 - 8
= x3 - 23
= (x - 2) (x2 + 2.x + 22)
= (x - 2)(x2 + 2x + 4)
∴ নির্ণেয় ল. সা. গু = (x + 2)2(x - 2)(x2 + 2x + 4)
=(x + 2)2(x3 - 8)
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