X and Y are two alloys of silver and gold prepared by mixing metals in the ratio 4 : 6 and 15 : 5 respectively. If equal quantities of the alloys are melted to form a third alloy Z, then ratio of gold and silver in Z will be
Solution
Correct Answer: Option E
In alloy X per (4 + 6) 10 unit, siver is 4 and gold is 6.
In alloy Y per (15 + 5) 20 unit, silver is 15 and gold is 5.
So to mix X and Y in equal quantity we need 2 × X for each Y.
So 2 × X means:
silver : gold = 8 : 12
Now alloy Z = X + Y = 8 : 12 + 15 : 5 = 23 : 17.
Therefore new alloy has silver : gold at 23 : 17 ratio or gold : silver at 17 : 23 ratio.
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