The average weight of 3 men A, B and C is 96kg. Another man D joins the group and the average now becomes now 88 kg. if another man E, whose weight is 4 kg more than that of D, replace A, then the average weight B, C, D and E becomes 82 kg. The weight of A is:
Solution
Correct Answer: Option C
Let the weights of A, B, C, D, E be a, b, c, d, e kgs respectively.
We know that, Average = (Sum of all terms)/(Number of terms)
∴ Sum of all terms = Average × number of terms
∵ Average of a, b, c is 96,
a + b + c = 3 × 96 = 288
∵ Average of a, b, c, d is 88,
a + b + c + d = 4 × 88 = 352
∴ d = 352 - 288 = 64
∵e is 4 more than d, e = 64+ 4 = 68
Now, since the average of b, c, d, e is 82,
b + c + d + e = 4 × 82 = 328
∴b + c = 328 - d - e = 328 - 64 – 68
⇒ b + c = 196
a = (a + b + c) - (b + c) = 288 - 196 = 92
Weight of A = 92 Kg
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