A number is 50% less than the third number and another number is 54% less than the third number. By how much percent is the second number less than the first number?
Correct Answer: Option E
Let the third number be 100x.
Then, First number = 50x
And second number = 46x
Now, difference = 50x – 46x = 4x
Required percentage = (4x/50x) × 100
= 8 %
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