What is the L.C.M and H.C.F of the fractions \(\frac{6}{5},\frac{3}{5}{\text{and}}\frac{{15}}{{11}}?\)
Correct Answer: Option A
As we know that,
\({\text{L}}.{\text{C}}.{\text{M of fractions}} = \frac{{{\text{LCM of numerators}}}}{{{\text{HCF of denominators}}}}\)
\({\text{H}}.{\text{C}}.{\text{F of fractions}} = \frac{{{\text{HCF of numerators}}}}{{{\text{LCM of denominators}}}}\)
Since, 6 = 2 × 3 3 = 1 × 3 15= 3 × 5 5 = 1 × 5 and 11 = 1 × 11
So L.C.M of 6, 3 and 15 = 2 × 3 × 5 = 30
And H.C.F of 5, 5 and 11 = 1
Hence L.C.M of \(\frac{6}{5},\frac{3}{5}{\text{and}}\frac{{15}}{{11}} = \frac{{30}}{1} = 30\)
Similarly H.C.F of 6, 3 and 15 = 3
And L.C.M of 5, 5 and 11 = 55
Hence H.C.F of \(\frac{6}{5},\frac{3}{5}{\text{and}}\frac{{15}}{{11}} = \frac{3}{{55}}\)
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