In a simultaneous throw of two dice, what is the probability of getting a total of 7?

A 1/2

B 1/3

C 1/4

D 1/6

E None of these

Correct Answer: Option D

In a simultaneous throw of two dice –

Number of possible outcomes n(s) = 6 × 6 = 36

Number of favourable events = n(E) = {(1, 6); (2, 5), (3, 4), (4, 3), (5, 2), (6,1)}

⇒ n(E) = 6

∴ Required probability of getting a total of 7 –

\(P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}}\)

\(= \frac{6}{{36}} = \frac{1}{6}\)