In the following question, one or two equation(s) is/are given. On their basis you have to determine the relation between x and y and then give answer
I. 3x2 + 7x = 6
II. 6(2y2 + 1) = 17y
Correct Answer: Option C
3x2 + 7x = 6
⇒ 3x2 + 7x - 6 = 0
⇒ 3x2 + 9x - 2x - 6 = 0
⇒ 3x (x + 3) - 2 (x + 3) = 0
⇒ (3x - 2) (x + 3) = 0
⇒ 3x - 2 = 0 or x + 3 = 0
⇒ x= 2/3 or -3
Equation 2:
6(2y2 + 1) = 17y
⇒ 12y2 + 6 = 17y
⇒ 12y2 – 17y + 6 = 0
⇒12y2 – 9y – 8y + 6 = 0
⇒ 3y (4y- 3) – 2 (4y - 3) = 0
⇒ (3y- 2) (4y - 3) = 0
⇒ 3y – 2 = 0 and 4y - 3 = 0
⇒ y = 2/3 and 3/4
Comparing values of x and y
x ≤ y
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