Two kinds of rice are sold at same price in which 10% is gained on one kind and 10% is lost on the other. If they be mixed equally and sold at the same price, what percentage will be gained or lost?
Correct Answer: Option B
Let’s assume the cost price of first kind of rice be Rs. x/kg
And, the cost price of second kind of rice be Rs. y/kg
According to the given information,
Selling price of first kind of rice = x + (10% of x) = 1.1x
Selling price of second kind of rice = y – (10% of y) = 0.9y
∵ Selling price of both rices are same
⇒ 1.1x = 0.9y
⇒ x = (9y/11)
∵ Both kind of rices are mixed in equal proportion,
⇒ Cost price of the mixture per kg = Rs. (x + y)/2
⇒ Cost price of the mixture \(= \;\frac{{y + \frac{{9y}}{{11}}}}{2}\; = \;\frac{{10y}}{{11}}\)
∵ the mixture is sold at the same price as before,
Selling price of mixture per kg = 0.9y \(= \;\frac{{9y}}{{10}}\)
As we can see by comparison that selling price < Cost price
∴ loss will be incurred in this transaction.
We know that, % Loss \(= \frac{{Cost\;price\;-\;Selling\;price}}{{Cost\;Price}} \times 100\)
∴% Loss \(= \frac{{\left( {\frac{{10y}}{{11}}} \right)\;-\left( {\frac{{9y}}{{10}}} \right)}}{{\left( {\frac{{9y}}{{10}}} \right)}} \times 100\)
⇒ % loss = 1
∴ There was a loss of 1%
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