If the probability that A will live 15 years is \(\frac{7}{8}\) and that B will live 15 years is \(\frac{9}{{10}}\) hen what is the probability that both will live 15 years?
Correct Answer: Option B
Probability of living of A and B are mutually exclusive.
Hence, P(AUB)= P(A) × P(B). Hence, the probability that both will live 15 years = \(\left( {\frac{7}{8} \times \frac{9}{{10}}} \right) = \frac{{63}}{{80}}\)
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