Two dice are tossed. The probability that the total score is a prime number is :
Correct Answer: Option B
When S is the sample space,
Probability of occurrence of the event, P(E) \(= \frac{{Number\;of\;favorable\;outcome,\;n\left( E \right)}}{{Number\;of\;possible\;outcome,\;n\left( S \right)}}\)
In a simultaneous throw of two dice, total number of possible combinations = n(S) = 6 × 6 = 36
Let E be the event when the sum of both numbers is a prime number
E = {(1, 1), (2, 1), (1, 2), (1, 4), (4, 1), (2, 3), (3, 2), (1, 6), (6, 1), (3, 4), (4, 3), (5, 2), (2, 5), (5, 6), (6, 5)}
n(E) = 15
∴ Probability P(E) = n(E)/n(S) = 15/36 = 5/12
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