If area of a rhombus is 225 cm2. One of the diagonal is half of the other diagonal. The sum of the diagonals would be:
Correct Answer: Option A
Let first diagonal is x cm, then the other one would be 2x cm
]Now, formula
Area of a rhombus = (1/2)×product of its diagonals
\(\eqalign{ & \Rightarrow 225 = \frac{1}{2} \times 2x \times x \cr & \Rightarrow {x^2} = 225c{m^2} \cr & \Rightarrow x = 15cm \cr}\)
Then the diagonals would be 15 cm and 30 cm
∴ Sum of the diagonals = 45 cm
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