Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is
Correct Answer: Option A
required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with à = 60 degrees and r = 3.5cm)
\(\left(\frac{\sqrt3}4\ast7\ast7\right)-\left(3\ast\frac{22}7\ast3.5\ast3.5\ast\frac{60}{360}\right)\) sq cm
\(\left(\frac{\sqrt3}4\ast49\right)-\left(11\ast0.5\ast3.5\right)\) sq cm
= 1.967 sq cm
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