A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
Correct Answer: Option A
Let the areas of the two parts be x and (700-x) hectares
therefore, \(\left[x-\left(700-x\right)\right]=\frac15\left[\frac{x+\left(700-x\right)}2\right]\)
\(\Rightarrow2x-700=70\)
\(\Rightarrow x=385\)
So, the two parts are 385 and 315.
Hence, Area of the smaller = 315 hectares
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