16 children are to be divided into two groups A and B of 10 and 6 children. The average percent marks obtained by the children of group A is 75 and the average percent marks of all the 16 children is 76. What is the average percent marks of children of group B ?
Solution
Correct Answer: Option D
Required average = \(\frac{\lbrack(76\;\times\;16)\;-\;(75\;\times\;10)\rbrack}6\)
= \(\frac{(1216\;-\;750)}6\)
= \(\frac{466}6\)
= \(\frac{233}3\)
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