The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then :
Solution
Correct Answer: Option B
Total of all 6 numbers = 6 × x = 6x
Total of the first 3 numbers = 3 × y = 3y
Total of the remaining 3 numbers = 3 × z = 3z
So,
6x = 3y + 3z
Now divide both sides by 3:
2x = y + z
Total of the first 3 numbers = 3 × y = 3y
Total of the remaining 3 numbers = 3 × z = 3z
So,
6x = 3y + 3z
Now divide both sides by 3:
2x = y + z
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