Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B ?
Solution
Correct Answer: Option C
circumference of A = \(2\mathrm{πr}\) = 8 => so r = \(\frac4{\mathrm\pi}\)
volume = \(\mathrm\pi\times\left(\frac4{\mathrm\pi}\right)^2\times10\) = \(\frac{160}{\mathrm\pi}\)
circumference of B = \(2\mathrm{πr}\) = 10 => so r = \(\frac5{\mathrm\pi}\)
volume = \(\mathrm\pi\times\left(\frac5{\mathrm\pi}\right)^2\times8\) = \(\frac{200}{\mathrm\pi}\)
so ratio of capacities = 160/200 = 0.8
so capacity of A will be 80% of the capacity of B.
Practice More Questions on Our App!
Download our app for free and access thousands of MCQ questions with detailed solutions