At what angle the hands of a clock are inclined at 15 minutes past 5?
Correct Answer: Option B
Angle traced by hour hand in \(\frac{21}4\) 21 hrs = \(\left(\frac{360}{12}\times\frac{21}4\right)^0\) = \(157\frac{1^0}2\)
Angle traced by min. hand in 15 min = \(\left(\frac{360}{12}\times15\right)^0\) = \(90^0\)
Required Angle = \(\left(157\frac12\right)^0-90^0\) = \(67\frac{1^0}2\)
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