At 3.40, the hour hand and the minute hand of a clock form an angle of:

A 110

B 120

C 130

D  140

Solution

Correct Answer: Option C

Angle traced by hour hand in 12 hrs. = 360º. 

 

Angle traced by it in \(\frac{11}3\) hrs = \(\left(\frac{360}{12}\times\frac{11}3\right)^0\) = \(110^0\)

Angle traced by minute hand in 60 min. = \(360^0\)

Angle traced by it in 40 min = \(\left(\frac{360}{60}\times40\right)^0\) = \(240^0\)

Required angle (240 - 110)º = \(130^0\)

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