What is the remainder when \(15^{23}+23^{23}\) is divided by 19 ?
Correct Answer: Option D
\(15^{23}+23^{23}=\left(19-4\right)^{23}+\left(19+4\right)^{23}\)
The remainder on dividing by 19 will be \(\left(-4\right)^{23}+\left(4\right)^{23}\) = 0
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